Home
tan 90
Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875

Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A) = - Maths - Trigonometric Functions - 13499875

4.6 (129) · $ 19.50 · In stock

cot left(frac{90-theta}{tan theta}+frac{csc (90-theta) sin theta}{tan (90 -theta)}=sec ^{2} thetaright. )

Prove that `(tan A)/((1-cot A))+(cot A)/((1-tan A))=(1+ tan A+cot A). `

Q149, Prove that (sec⁡A-tan⁡A)/(cosec⁡A+cot⁡A)=(cosec⁡A-cot⁡A)/(sec⁡A+tan⁡A)

What is the formula of tan(90 - A)? - Quora

How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora

A Trigonometric Equation with Tan and Cot

How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora

How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora

How can we prove Tan (90-theta) +cot (90-theta) =cosec (theta) *sec (theta)? - Quora

How to prove that: tanA/1-cotA+cotA/1-tanA=secAcosecA+1 - Quora

$\\=\frac{(1+\cot A+\tan A)(\sin A-\cos A)}{sec^3 A - \csc^3 A}\\\\\\ =\frac{\left (1+\frac{\sin A}{\cos A} + \frac{\cos A}{\sin A} \right )(\sin A-\cos A)}{\frac{1}{\cos^3A}-\frac{1}{\sin^3A}}\\\\\\ =\frac{\left (\frac{\sin A.\cos A+\sin^2A+\cos^2A}{\sin A .\cos A} \right )(\sin A-\cos A)}{\frac{\sin^3A-\cos^3A}{\sin^3A.\cos^3A}}\\\\\\ =\frac{\left (\sin A.\cos A+\sin^2A+\cos^2A \right )(\sin A-\cos A)}{\sin A .\cos A}\times\frac{\sin^3A.\cos^3A}{\sin^3A-\cos^3A}\\\\\\ (\text{By the identity: } (a-b)(a^2+b^2+ab)=a^3-b^3)\\\\\\ =\frac{\sin^3A-\cos^3A}{\sin A .\cos A}\times\frac{\sin^3A.\cos^3A}{\sin^3A-\cos^3A}\\\\\\ =\sin^2A.\cos^2a\\\\=RHS$

Show that:(1+cotA+tanA)(sinA-cosA) / sec^3 A - cosec^3 A Introduction to Trigonometry-Maths-Class-10

If A + B = 90° then tanA tanB + tanA cotB / sinA secB - sin^2 B / cos^2 A = is equal to: - Sarthaks eConnect