∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in
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∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?
Fig 11.25 △ABC is isosceles with AB=AC=7.5 cm and BC=9 cm (Fig
DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD
ΔABC is isosceles with AB=AC=7cm and BC=9cm. The height AD from A
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Question 8. AABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm
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NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex
DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD from
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex
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Infic is isosceles with ( mathrm { AB } = mathrm { AC } = 7.5
