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compression factor equation
SOLVED: For a gas at a given temperature, the compression factor is described by the empirical equation: z = 1 - 8.50 Ã— 10^(-3)P/PÂ° + 3.50 Ã— 10^(-5)(P/PÂ°)^2 where PÂ° = 1

SOLVED: For a gas at a given temperature, the compression factor is described by the empirical equation: z = 1 - 8.50 Ã— 10^(-3)P/PÂ° + 3.50 Ã— 10^(-5)(P/PÂ°)^2 where PÂ° = 1

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VIDEO ANSWER: Hello students: let's look at the question: l n, that integrate integration and 0 z minus 1 bracket, close d p by p here. Minus 1 is equal to minus 8.50 into 10 to the power minus 3 p by p, not plus 3.50 into 10. To the power minus 9. P
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SOLVED: For a gas at a given temperature, the compression factor is described by the empirical equation z=1-8.50 × 10^-3(P)/(P^∘)+3.50 × 10^-5(( P)/(P^∘))^2 where P^∘=1 bar. Calculate the fugacity coefficient for P=150 .